Reports: Yoshinobu Yamamoto, Dodgers agree to 12-year, $325 million deal

Aug 4, 2021; Yokohama, Japan; Team Japan pitcher Yoshinobu Yamamoto (17) throws a pitch against Korea in a baseball semifinal match during the Tokyo 2020 Olympic Summer Games at Yokohama Baseball Stadium. Mandatory Credit: Yukihito Taguchi-USA TODAY Sports

Credit: Yukihito Taguchi-USA TODAY Sports

After signing reigning American League MVP Shohei Ohtani to a 10-year, $700 million contract earlier this month, the Dodgers have landed star Japanese right-hander Yoshinobu Yamamoto with a 12-year, $325 million deal Thursday, per multiple media reports.

Yamamato’s deal would eclipse New York Yankees ace Gerrit Cole’s deal by $1 million, making it the largest contract for a pitcher in major league history. The Dodgers will also pay $50.6 million in a posting fee for Yamamoto.

The New York Yankees, New York Mets, Boston Red Sox, San Francisco Giants, Philadelphia Phillies and Toronto Blue Jays also pursued Yamamoto.

Yamamoto spent the past six-plus seasons with the Orix Buffaloes, compiling a 70-29 record with one save and a 1.82 ERA in 172 games. He has struck out 922 batters over 897 innings.

In 23 games in 2023, he finished with a 16-6 record and 1.21 ERA with 169 strikeouts in 164 innings. Those numbers helped him to his third straight Triple Crown in the Pacific League of Nippon Professional Baseball as he led the league in wins, ERA and strikeouts.

Only three pitchers in Major League Baseball have won the pitching Triple Crown three times — Sandy Koufax, Walter Johnson and Grover Cleveland Alexander.

Yamamoto also has won the Eiji Sawamura Award, which equals the Cy Young Award, three times.

The 5-foot-10 Yamamoto won a gold medal with Japan in the 2020 Tokyo Olympics and another in the World Baseball Classic earlier this year.

–Field Level Media

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